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টেক্সটাইল ইঞ্জিনিয়ারিং

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61. MCQPractice set · Question 61

2 - 2i এর argument কত?

a.
45°
b.
-45°
c.
135°
d.
-135°

Correct answer: b

বিন্দু (2, -2) চতুর্থ চতুর্ভাগে এবং tan θ = -1, তাই θ = -45°।

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62. MCQPractice set · Question 62

-i এর argument কত?

a.
-90°
b.
90°
c.
180°
d.

Correct answer: a

-i = 0 - i, অর্থাৎ বিন্দু (0, -1) negative imaginary axis-এ। তাই argument -90°।

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63. MCQPractice set · Question 63

z = i/(1 + i) এর argument কত?

a.
45°
b.
90°
c.
d.
-45°

Correct answer: a

i/(1 + i) = i(1 - i)/((1 + i)(1 - i)) = (i + 1)/2। লব ও হরের modulus সমান, তাই argument 45°।

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64. MCQPractice set · Question 64

De Moivre-এর theorem অনুযায়ী (cos θ + i sin θ)ⁿ = ?

a.
cos nθ - i sin nθ
b.
cos nθ + i sin nθ
c.
n(cos θ + i sin θ)
d.
cos θⁿ + i sin θⁿ

Correct answer: b

De Moivre-এর theorem: (cos θ + i sin θ)ⁿ = cos nθ + i sin nθ। এখানে modulus 1 থাকে, শুধু argument n গুণ হয়।

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65. MCQPractice set · Question 65

(1 + i)⁸ এর মান কত?

a.
16
b.
8
c.
16i
d.
-16

Correct answer: a

1 + i = √2(cos 45° + i sin 45°)। তাই (1 + i)⁸ = (√2)⁸(cos 360° + i sin 360°) = 16।

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66. MCQPractice set · Question 66

(1 - i)⁴ এর মান কত?

a.
4
b.
-4
c.
4i
d.
-4i

Correct answer: b

1 - i = √2(cos(-45°) + i sin(-45°))। তাই (1 - i)⁴ = 4(cos(-180°) + i sin(-180°)) = -4।

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67. MCQPractice set · Question 67

(√3 + i)⁶ এর মান কত?

a.
-64
b.
64
c.
64i
d.
-64i

Correct answer: a

√3 + i = 2(cos 30° + i sin 30°)। তাই ষষ্ঠ ঘাত = 2⁶(cos 180° + i sin 180°) = 64(-1) = -64।

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68. MCQPractice set · Question 68

(cos θ + i sin θ)(cos θ - i sin θ) = কত?

a.
1
b.
2
c.
cos 2θ
d.
cos 2θ + i sin 2θ

Correct answer: a

দুইটি সংখ্যা পরস্পরের conjugate এবং modulus 1, তাই গুণফল = |z|² = 1।

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69. MCQPractice set · Question 69

z = cos θ + i sin θ হলে zⁿ + z⁻ⁿ = কত?

a.
2i sin nθ
b.
2 cos nθ
c.
cos nθ
d.
0

Correct answer: b

zⁿ = cos nθ + i sin nθ এবং z⁻ⁿ = cos nθ - i sin nθ; যোগ করলে 2 cos nθ।

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70. MCQPractice set · Question 70

z = cos θ + i sin θ হলে zⁿ - z⁻ⁿ = কত?

a.
2i sin nθ
b.
2 sin nθ
c.
2i cos nθ
d.
i

Correct answer: a

zⁿ - z⁻ⁿ = (cos nθ + i sin nθ) - (cos nθ - i sin nθ) = 2i sin nθ।

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