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1041. MCQPractice set · Question 108

একটি object-এর v-t graph-এর area zero হলে কী হতে পারে?

a.
net displacement zero
b.
distance zero অবশ্যই
c.
acceleration zero
d.
velocity সবসময় zero

Correct answer: a

Positive ও negative signed areas cancel হলে net displacement zero হতে পারে।

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1042. MCQPractice set · Question 109

একটি body-এর displacement zero হলেও distance non-zero হতে পারে?

a.
হ্যাঁ, ফিরে এলে
b.
না
c.
শুধু rest-এ
d.
শুধু straight line-এ

Correct answer: a

Closed বা return path-এ distance positive কিন্তু displacement zero।

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1043. MCQPractice set · Question 110

Uniform motion-এ acceleration কত?

a.
zero
b.
g
c.
constant positive
d.
infinite

Correct answer: a

Uniform velocity-এর change zero, তাই acceleration zero।

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1044. MCQPractice set · Question 111

Motion equation ব্যবহার করতে acceleration কেমন হতে হয়?

a.
constant
b.
যেকোনো variable
c.
শুধু zero
d.
শুধু negative

Correct answer: a

v=u+at, s=ut+½at² ইত্যাদি constant acceleration-এর জন্য।

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1045. MCQPractice set · Question 112

Equation s=ut+½at²-এ a negative হলে কী বোঝায়?

a.
chosen positive direction-এর বিপরীত acceleration
b.
speed negative
c.
time negative
d.
distance negative অবশ্যই

Correct answer: a

Acceleration-এর sign reference direction-এর relative orientation নির্দেশ করে।

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1046. MCQPractice set · Question 113

u=0, v=20 m/s, a=5 m/s² হলে displacement কত?

a.
20 m
b.
40 m
c.
50 m
d.
80 m

Correct answer: b

v²=2as থেকে 400=10s, তাই s=40 m।

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1047. MCQPractice set · Question 114

u=10 m/s, v=0, a=−2 m/s² হলে stopping distance কত?

a.
10 m
b.
20 m
c.
25 m
d.
50 m

Correct answer: c

0=100−4s, তাই s=25 m।

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1048. MCQPractice set · Question 115

u=10 m/s, a=−2 m/s² হলে 3 s পরে velocity কত?

a.
−4 m/s
b.
4 m/s
c.
6 m/s
d.
16 m/s

Correct answer: c

v=10−2×3=4 m/s; সঠিক option b।

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1049. MCQPractice set · Question 116

u=10 m/s, a=−2 m/s² হলে 3 s পরে velocity কত?

a.
−4 m/s
b.
4 m/s
c.
6 m/s
d.
16 m/s

Correct answer: b

v=u+at=10−2×3=4 m/s।

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1050. MCQPractice set · Question 117

u=10 m/s, a=−2 m/s² হলে 3 s-এ displacement কত?

a.
12 m
b.
18 m
c.
21 m
d.
30 m

Correct answer: c

s=ut+½at²=30−9=21 m।

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